A girl pushes her little brother on his sled with a force of 300. N for 750. m. How
much work is this if the force of friction acting on the sled is (a) 200. N, (b)
300. N?
Answers
Answered by
6
Explanation:
(a) resultant force acting = 300N - 200 N= 100N
displacement=750m
work done =force * displacement
100*750=75000
(b) resultant force acting =0
work done =0
Answered by
11
Work done is 75 kJ if force of friction is 200N and no work done if force of friction is 300 N
Given:
- Anna pushes her little brother on his sled with a force of 300N for 750m.
To Find:
- Work done if the force of friction acting on the sled is
- a) 200 N
- b) 300 N
Solution:
- Work Done = Net Force x Displacement
Net Force = Force Applied - Force Against
In this case:
Net Force = Force Applied - Frictional Force
Step 1:
Find net force when force of friction is 200 N
Net Force = 300 - 200 = 100 N
Step 2:
Calculate the work done
Work Done = 100 x 750 = 75000 J = 75 kJ
Step 3:
Find net force when force of friction is 300 N
Net Force = 300 - 300 = 0 N
Step 4:
Calculate the work done
Work Done = 0 x 750 = 0 J
Means no work done
Work done is 75 kJ if force of friction is 200N and no work done if force of friction is 300 N
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