Math, asked by haritendulkar4674, 1 year ago

A girl read 2/5 part of a book in 1st day, 34% in second day and remaining page in next two days. In two days she read equal number of page. If she read 52 pages on last day, then find out how many pages did the book contain?
A) 400
B) 376
C) 382
D) 356

Answers

Answered by sakshi7048

$<b><body bgcolor="orange">$ hey mate

here's your answer,

》 1st day the girl read = $\huge\frac{2}{5}$ × 100%

= 2 × 20% = 40%

》 on 2nd day = 34%

so ,

100% -(40%+34%) = 100% - 74% = 26%

now , as given in question that she read the same no. of pages in the last two days ,

》 $\huge\frac{26\:percent }{2}$ = 13%

according to question she reads 52 pages on last say ,

》 13% = 52

1% = $\huge\frac{52}{13}$ = 4

》 100% = 400 pages

$\hence$ The book contains 400 pages.

hope it helps you mate ✌✌

be brainly ✌✌

♥️♥️BY SAKSHI SINGH ♥️♥️

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A girl read 2/5 part of a book in 1st day, 34% in second day and remaining page in next two days. In two days she read equal number of page. If she read 52 pages on last day, then find out how many pages did the book contain? A) 400 B) 376 C) 382 D) 356

Answers

A girl read 2/5 part of a book in 1st day, 34% in second day and remaining page in next two days. In two days she read equal number of page. If she read 52 pages on last day, then find out how many pages did the book contain?
A) 400
B) 376
C) 382
D) 356