Question

A girl read 2/7th of the book on one day and 4/5th of the remainders on another day. If ther were 35 pages unread, how many pages did the book contain?


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Answer 1

175 pages book contains

Answer 2

Let
total pages in the book =x

2/7 of x pages =2/7x

Remaining =x-2x/7

=7x-2x/7

=5x/7

Now 4/5 of remaining =(5x/7) X(4/5)

=20x/35

Unread pages=(5x/7)-(20x/35)

$= \frac{5x}{7} - \frac{20x}{35}$
$= \frac{(5 \times 5x) - 20x}{35}$

$= \frac{25x - 20x}{35}$
$= \frac{5x}{35}$
This will be equal to 35

5x/35=35

5x=35x35

X=35x7

X=245

Total pages =245


Verification

2/7 of 245=70

Unread remaining =245-70

=175

4/5 of 175=140

Unread pages =175-140

=35

Verified

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