A girl running a race accelerate at 2.5ms-1 for the first four second of the race how far does she travel in this time
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u= 0
Time = 4 s
a= 2.5m/s^2
Using third equation of motion
Distance = ut+(1/2)at^2
= (0)(4)+ (1/2)(2.5)(4)(4)
= 0+ 20
= 20m
So, the girl covered 20m in the first four seconds in the race.
Time = 4 s
a= 2.5m/s^2
Using third equation of motion
Distance = ut+(1/2)at^2
= (0)(4)+ (1/2)(2.5)(4)(4)
= 0+ 20
= 20m
So, the girl covered 20m in the first four seconds in the race.
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