A girl saves rs 3,60 daily. Find the list number of days in which she will be able to save and exact number of rupees.
show the method
Answers
Answer:
Step-by-step explanation:
Hint: We need to find the least number of days in which he will be also to save an exact number of rupees. We will convert the given rupees to paise and take 100 paise for one rupee and then we take the l.c.m. of 465 and 100 we will get the required number. By dividing the least common multiple by converted paise amount.
Complete step-by-step answer: It is given that the boy saves Rs 4.65 daily.
Rs.4.65= 465paisa
First see the number 4.65.
If we multiply it by any single number1,2,3,4,…8,9
, we will get a number with a decimal point.
Let us take the number 10 then, 4.65×10=46.50
which is also not an exact number.
The exact number of rupees will be multiple of 100
So, let us find the least common multiple of 465 and 100.
To find the least common multiple of both the numbers we should prime factorize them.
The prime factorization of,
100=2×2×5×5
465=3×5×31
Least common multiple of 465 and 100 is 2×2×5×3×5×31=9300
Thus, the boy saves 9300paisa=Rs93
To find the least number of days to make the saving exact we must divide the total paisa the boy saved by his saving per day.
That is the least number of days required to save 9300 paisa = 9300465=20days
Therefore, the least number of days in which he will be also to save an exact number of rupees is 20 days.
Note: LCM: The least common multiple of two integers a and b, usually denoted by
lcm(a,b)
, is the smallest positive integer that is divisible by both “a” and “b”.
Here we do not use the greatest common divisor to solve the problem because we have to find the least number of days.
Exact number is the whole number which does not have any decimal places.
We have used Rs.1=100paisa
Answer:
In 5 days she will save 18 rupees
Step-by-step explanation:
3.6^5 = 18
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