Question

A girl standing upright exerts a pressure of 13600Nm^-2 on the floor .Given that the total area of contact of shoes and the floor is 0.036m². i)determine the mass of the girl .i) determine the pressure she would exert on the floor if she stood on one foot.​

Answer 1

Answer:

p=13600 N/m²

A=0.036m²

F=?

F=PxA

=13600×0.036N

=489-6N

F=mxg

or,m=F÷g

or, m=489.6÷9.8-50 kg

Answer 2

$\blue{\mathfrak{\underline{\large{Given}}}:} \\ pressure \: on \: the \: floor(P) = 13600 \: N {m}^{ - 2} \\ area \: of \:contact \: and \: the \: floor(A) = 0.036 \: {m}^{2} \\ \blue{\mathfrak{\underline{\large{To \: find}}}:} \\ mass \: of \: the \: girl(m) = ? \\ pressure \: exerted \: by \: on \: foot \: of \: girl(let \: say \: P°) = ? \\ \blue{\mathfrak{\underline{\large{Findng}}}:} \\ (i): P = \frac{F}{A} \\ mg = P \times A \\ m = \frac{P \times A}{g} \\ m = \frac{13600 \times 0.036}{10} \\ \boxed{m = 48.96 \: kg} \\ \\ (ii) : when \: the \: girl \: stood \: on \: one \: foot \: the \: \\ area \: become \: half \\ so, \: \: A° = \frac{0.036}{2} = 0.018 \: {m}^{2} \\ \\ P° = \frac{F}{A°} \\ = \frac{48.96 \times 10}{0.018} \\ \boxed{P° = 27200 \: N {m}^{ - 2} } \\ \\ \red{\mathfrak{ \large{\underline{{Hope \: It \: Helps \: You}}}}} \\ \blue{\mathfrak{ \large{\underline{{Mark \: Me \: Brainliest}}}}}$