Question

a girl starts her motion in a straight line at a speed of 3m/s (her velocity is changing at a constant rate) if she stops at 60s what is her acceleration?​

Answer 1

u = 3 m/s

v = 0 m/s

t = 60 s

a = (v - u)/t

= (0 - 3)/60

= -3/60

= - 0.05 m/s² (Answer)

Answer 2

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✴️Final answer :-

-0.5 m/s ^2

✴️Given :-

U = 30m/s

V =*0m/s

T = 60 seconds.

Acceleration = v-u/t

= 0-30/60

= - 30/60

= - 3/6

= - 0.5 m/s^2

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Hope it helped ✌️