Question

a girl starts her motion in a straight line at a velocity of 30 m/s , her velocity is changing at constant rate. if she stops after 60s. what is her acceleration​

Answer 1

Answer:

-0.5 m/s²

Step-by-step explanation:

Given:- u= 30m/s

v= 0 m/s

t= 60secs

Acceleration=v-u/t

= 0-30/60

= -30/60

=-3/6

=-1/2

= -0.5 m/s²

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Answer 2

Given:

• The initial velocity = 30 m/s
• The final velocity = 0 m/s
• Time = 60 s

To Find:

• The acceleration of the girl in motion.

Solution:

The formula to find acceleration is given by,

acceleration = (change in velocity)/(time taken)

a = (u-v)/t → {equation 1}

Where "u" is the final velocity, "v" is the initial velocity, "t" is the time taken.

Substitute the values from the given data in equation 1. We get,

a = (0-30)/60  { subtracting the terms in the numerator}

a = -30/60 = -1/2 { dividing the terms}

a = -0.5 m/$s^2$  { converted fraction into decimal}

∴ The acceleration of the girl in motion = -0.5 m/$s^2$.