Math, asked by sumukhasreenidh2788, 10 months ago

A girl starts walking from her house and travels a distance of 10km to the North. Then she takes a right turn and travels 5km after which she travels 20km South. What is the distance between her house and the final destination?

Answers

Answered by ganesh442006
0

Answer:

5km

Step-by-step explanation:

because

first she travelled 15km north

then she travelled 20km south

so 20-15=5km in south directiom

Answered by sharonr
1

The distance between her house and the final destination is 11.18 km

Solution:

Given that,

A girl starts walking from her house and travels a distance of 10km to the North

Then she takes a right turn and travels 5km after which she travels 20km South

The figure for solving the problem is attached below

Let 'O" be the starting point

OA = distance of 10km to the North

AB = she takes a right turn and travels 5km

BC = after which she travels 20km South

Since, BC = 20 km

AO = 10 km

Thus, DC = 20 - 10 = 10 km

Also,

AB = OD = 5 km

We have to find distance between her house and the final destination

Which means, we have to find length of OC

Also, CDO forms a right angled triangle,

By pythogoras theorem,

OC^2 = OD^2 + DC^2

From attached figure,

DC = 10 km

OD = 5 km

Therefore,

OC^2 = 5^2 + 10^2\\\\OC^2 = 25 + 100\\\\OC^2 = 125\\\\TAKE\ SQUARE\ ROOT\ ON\ BOTH\ SIDES\\\\OC = 11.18

Thus, the distance between her house and the final destination is 11.18 km

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