A girl throws a ball vertically upwards at a initial velocity 20 ms-1 then catches it some time later. Calculate the time taken for ball to return to the same height as it was released
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Answer:
4 seconds
Explanation:
Equation of linear motion
S= ut-1/2gt2
S=0m
0=ut -1/2gt2
ut =1/2gt2
Divide through by t
u =1/2gt
20=1/2*10*t
20=5t
t=20/5
=4seconds
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