Question

A girl took 1g of lime stone to examine after examining how many particles would she find???

Answer 1

Hey there,

Formula of limestone=CaCO₃
Molecular mass=100
No of moles=Given mass/molecular mass=1/100
So number of particles=Avogadro number/150=6.022*10²³/100 particles
=6.023*10²¹ particles

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Answer 2

We know that

Formula of Limestone = CaCO3


Gram molecular weight of lime stone =40+12+3*16 = 100 g

1 mole of limestone => 100 g of limestone.

According to avogadro,
1 mole of limestone = 6.023*10^23 particles

So, 100 g of limestone = 6.023*10^23
particles.

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100 g of limestone ---> 6.023*10^23 particles.

1 g of limestone ----> x.


x * 100 = 6.023*10^23


x = 6.023*10^23-2

x = 6.023*10^21.

A girl took 1g of lime stone to examine after examining she would find 6.023*10^21 particles.