Question

A girl walks 200 towards East and the she walks 150m towards North. Find the distance of the
girl from the starting point.

Answer 1

you can out the answer by pythogoras theorem

√200²+150²
√40000+22500
√62500
250 m is the answer

Answer 2

Answer:

250 m

Step-by-step explanation:

Refer the attached figure

We are given that A girl walks 200 towards East i.e. AB = 200

We are also given that she walks 150m towards North. i.e.BC = 150

To find AC we will use Pythagorean theorem

$Hypotenuse^{2} =Perpendicular^{2} +Base^{2}$

$AC^{2} =BC^{2} +AB^{2}$

$AC^{2} =150^{2} +200^{2}$

$AC^{2} =22500+40000$

$AC^{2} =62500$

$AC =\sqrt{62500}$

$AC =250$

Thus the  the distance of the  girl from the starting point is 250 m.