A girl walks along a straight path to drop a letter in the letterbox and comes back to her initial position. Her displacement–time graph is shown in Fig.8.4. Plot a velocity–time graph for the same.
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From the graph of displacement time graph, we can interpret that initial velocity is 0 as displacement and time are 0 .
Velocity after 50 seconds;
= 100/50
=2 m/s
= velocity after 100sec
=zero
Velocity with time table is given below :
V 0 2 0
t 0 50 100
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Answer:
From the graph
(1) initial velocity, u=0
(2)velocity after 50s,v=displacement/time
V=100/5=2ms^-1
(3)velocity after 100s,V=displacement/time
V=0/100=0
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