Math, asked by ShoaibAkmal, 10 months ago

A girl was standing with her face pointing to the south-east direction. She walked
15 metres and then turned towards her North and walked another 20 metres. How
far was she then from the starting point?

please write solution as well​

Answers

Answered by saniya7826
1

Answer:

not able to understand your question

Answered by mhanifa
4

Answer:

14.2 m

Step-by-step explanation:

see the attached solution, it is self explanatory

Girl moves from A to B to C, AC is the distance to be found

  • AB=15 m, BC= 20 m, AC=?  
  • AD=BD as  ∠DAB=45 deg  
  • x²= AD²+CD²  
  • CD²=(20-BD)²  
  • AD²=15²/2  
  • x²= 15²/2+(20-√15²/2)²  
  • x²= 201  
  • x=√201  
  • x=14.2 m
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