A girl was standing with her face pointing to the south-east direction. She walked
15 metres and then turned towards her North and walked another 20 metres. How
far was she then from the starting point?
please write solution as well
Answers
Answered by
1
Answer:
not able to understand your question
Answered by
4
Answer:
14.2 m
Step-by-step explanation:
see the attached solution, it is self explanatory
Girl moves from A to B to C, AC is the distance to be found
- AB=15 m, BC= 20 m, AC=?
- AD=BD as ∠DAB=45 deg
- x²= AD²+CD²
- CD²=(20-BD)²
- AD²=15²/2
- x²= 15²/2+(20-√15²/2)²
- x²= 201
- x=√201
- x=14.2 m
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