A girl weighing 50 kg and wearing a heeled pair of shoes of area 5 cm2 is standing on a horizontal floor. What is the pressure applied by her on the floor?
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Answer:
Mass of the girl, m=50kg
Diameter of the heel, d=1cm=0.01m
Radius of the heel, r=
2
d
=0.005m
Area of the heel =πr
2
=π×(0.005)
2
=7.85×10
−5
m
2
Force exerted by the heel on the floor:
F=mg
=50×9.8
=490N
Pressure exerted by the heel on the floor:
P=
Area
Force
=490/(7.85×10
−5
)=6.24×10
6
N/m
2
Therefore, the pressure exerted by the heel on the horizontal floor is 6.24×10
6
N/m
2
.
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