Question

A girl weighs 36 kg. She is standing on the ground . If area of either foot of kashvi is 150 cm ² , then calculate the pressure exerted by her on the ground.
Take g = 10 m/s ²

Answer 1

Question :

A girl weighs 36 kg. She is standing on the ground . If area of either foot of kashvi is 150 cm ² , then calculate the pressure exerted by her on the ground.
Take g = 10 m/s ²

Answer :

Mass of girl = 36 kg .

g = 10 m/s²

Area of her either feet = 150 cm² = 150×10^-4 m²

Thrust , F = weight of the girl.

= mg = 36×10 = 360 N

Total area of her both feet = 2A = 2(150×10^-4) = 3×10 ^2 m²

Pressure = Thrust / Area = 360/3×10^-2 = 1.2×10⁴ Pa

So , the required pressure is = 1.2×10^-4 Pa .

Answer 2

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The answer goes here....

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Given,

Mass of girl = 36 kg

g = $10\:{ms}^{-1}$

Area of feet = $150\:{cm}^{2}$ = $150\times {10}^{-4}{m}^{2}$

Here,

⇒ $F$ = mg

⇒ $F$ = $36\times 10$

⇒ $F$ = $360\:N$

Now, the total area of both feets -

⇒ $2\times 150\times {10}^{-4}$

⇒ $3\times {10}^{2}{m}^{2}$

Now, we know that -

⇒ $Pressure$ = $\frac{Thrust}{Area}$

⇒ $Pressure$ = $\frac{360}{3\times {10}^{2}}$

⇒ $Pressure$ = $1.2\times {10}^{4}$ Pa

So, the pressure exerted by her on the ground is $1.2\times {10}^{4}$ Pa.

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Thanks !!..