Question

A girl with eyes - level height of 1.65m observers that the Angele of elevation of the top of a tower 20m away is 40 degrees. Calculate the height of the tower

Answer 1

here, value of tan40° must be provided otherwise plz check the value of angle of elevation...
Hope this helps u (^o^)

Answer 2

The height of the tower is 14.506 m.

Given:

Let us consider AD to be the eye level height of the girl, AD = 1.65 m

∠BAC = 40°

Let us consider The top of the tower is at B, then AB = 20 m

To Find:

The height of the tower.

Solution:

Here, we are required to find the height of the tower.

Let BE be the height of the tower.

From the diagram given below, BE = BC+CE ----(1)

To find the value of BC, From the triangle ABC we know

Sin θ° = opposite side/hypotenuse

Sin 40° = BC/20

BC = 20×sin 40°

     = 20×0.642789

     = 12.856 m

From the given diagram, CE = height of the eye level.

⇒ CE = 1.65 m

Substituting the value of BC and CE in (1)

BE = 12.856+1.65

     = 14.506 m

Therefore, The height of the tower is 14.506 m.

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