Question

(a) Give the output of the following string functions :
(i) “MISSISSIPPI”.indexOf(‘S’) + “MISSISSIPPI”.lastIndexOf(‘I’)
(ii) “CABLE”.compareTo(“CADET”)

Answer 1

Ans. 
(i) “MISSISSIPPI”.indexOf(‘S’) + “MISSISSIPPI”.lastIndexOf(‘I’)
= 2 + 10
= 12
(ii) String’s compareTo method compares ASCII values of characters starting from the left.
“CABLE”.compareTo(“CADET”)
The first and seconds characters are the same in both the strings. So, we compare the third characters.
Compare B and D = ASCII value of B – ASCII value of D
= 66 – 68
= -2

Answer 2

(i)Output:2+10=12

(ii)Output:-2