A given arteriole has a resistance of 4 . What would the new resistance of this vessel be if it's radius were to double ?
plz tell me answer with solution
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Answer:
The new resistance will be reduced to one fourth of original
Explanation:
it is known that:
R=resistivity * Length/area
Area=pi r^2
resistance is inversely related to the square of the radius
if radius is double so resistance is reduced to one fourth of the original value
Original value is 4 so after doubling the radius it becomes 1
hope it will help you
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