Physics, asked by bhola999970, 1 year ago

a given copper wire is stretched to reduce its diameter to half its previous value what would be its new resistance​

Answers

Answered by sujayraj24
4

Answer:

The resistance would be twice than it was before.

Explanation:

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sujayraj24: Ok
sujayraj24: R is inversely proportional to the cross section of the wire
sujayraj24: which means if d is havled
sujayraj24: radius is too halved
sujayraj24: therefore area will be reduced by 1/4th
sujayraj24: So Resistance is increased by 4 times
uday9310: yess
sujayraj24: I actually forgot about the cross section
uday9310: diameter of wire is half then wire length is 16 then diameter will be 8
uday9310: new resistance becomes 4time then actual wire then 16*4=64
Answered by uday9310
7

Explanation:

Thus new resistance becomes 4 times its original resistance when diametre of given wire is halfed. ... A copper wire with a resistivity of r is stretched to reduce its diameter to half of its previous value.

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bhola999970: no bro the answer is 16
uday9310: okay
uday9310: I thought wire length is 16
uday9310: sry
uday9310: make my answer as brain list answer please
uday9310: please
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