Question

A given length of a wire is double of itself and this process is repeated once again. By what factor does the resistance of the wire changes?

Answer 1

Let the resistance of the wire be R.

When the wire is doubled on itself and the process is repeated then - 

The length of the wire reduces by 1/2, and the area increases by 2 times. 

Thus, the resistance of the wire reduced by 1/4 times.

So, resistance = R/4

So, the total resistance of the wire when the resistors are arranged in parallel,

1/Rp = 1/(R/4) + 1/(R/4) + 1/(R/4) + 1/(R/4)

Rp = R/16
Thus, the resistance of the wire reduces by 16 times

Answer 2

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