A given length of a wire is doubled on itself.By what factor does the resistance of the wire changes?
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Explanation:
R=ρl/A
When you double a wire, length halves, and area doubles.
l=l/2
A=2A
New resistance:
R=ρl/2*A*2
=ρl/4A
So Resistance decreases by a factor of 4
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