A given length of wire is doubled of itself and this process is repeated once again. By what factor does the resistance of the wire changed? plz explain
Answers
Answered by
0
formula of resistance is:-
R = Rho x l/A
multiplaying and dividing by I we get:-
R = Rho x l^2/Al
Al= Volume which remains constent
now we double the length
R' (new resistance) = Rho x (2l)^2/AI
= Rho x 4I^2/ AI
= Rho x 4I/ A
= 4 x R
new resistance becomes 4 times of that of old resistance
all the best✌
R = Rho x l/A
multiplaying and dividing by I we get:-
R = Rho x l^2/Al
Al= Volume which remains constent
now we double the length
R' (new resistance) = Rho x (2l)^2/AI
= Rho x 4I^2/ AI
= Rho x 4I/ A
= 4 x R
new resistance becomes 4 times of that of old resistance
all the best✌
Answered by
0
Answer:
The length of wire is doubled on itself and so the area get reduced to half. The resultant resistance will be 4 times.
The process is repeated and therefore the resistance will increase by 4 times. The total resistance will be increased to 16 times.
Similar questions