Question

A given mass of a gas occupies 400 ml at 760mm bar pressure at 200 C.

What volume will the gas occupy if the pressure is increased to 1.025 bar,

temperature remaining constant?
want written answer ​

Answer 1

Explanation:

P

1

=0.820bar

P

2

=1.025bar

V

1

=200ml

V

2

=?

Since temperature is constant therefore, by applying Boyle's law,

P

1

V

1

=P

2

V

2

or V

2

=

P

2

P

1

V

1

V

2

=

1.025bar

(0.820bar)×(200mL)

=160ml

Answer 2

Explanation:

P1V1=P2V2

200×0.72=0.9×V2

V2=160 ml

P_(1)="0.820 "p_(2)="1.025 bar"

<br>

V_(1)="200 mL "V_(2)=?

<br> Since temperature is constant, therefore, by applying Boyle.s law, <br>

p_(1)V_(1)=p_(2)V_(2)" or "V_(2)=(p_(1)V_(1))/(p_(2))

<br>

V_(2)=(("0.820 bar")xx("200 mL"))/("1.025 bar")="160 ml"