A given mass of an ideal gas is heated in a vessel. The same amount of gas is then heated by keeping it in a larger vessel. Assume that the volumes of both vessel remain the same during heating. What will be the nature of the pressure temperature (p-T) graphs in the two cases.
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Explanation:
when the volume is less, the pressure increases with temperature at a higher rate.
So the slop of the p-T graph for the smaller container is greater than for the bigger container.
Alternative method:
For a fixed mass of an ideal gas,
pV=kTor,p=kVT.
IF V is fixed,this relation resembles y=mx.
So the p-T graph is a straight line passing through the origin.
Also the slope kv is higher for a smaller V. So the graph of the smaller vessel has a higher slope.
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