A given mass of nitrogen is 0.12 dm³at 60°C and 1.01 x 10^5N m^-2. Find its pressure at the same temperature if its volume is changed to 0.24 dm³.
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Explanation:
The formular is p1v1t1=p2v2t2
p1=1.01×10^5Nm^2
v1=0.12
t1=60
p2?
v2=0.24dm^3
t2=273
p2= v2t2/p1v1t1
multiply them and get your answer
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