A given number is a perfect square having n digits ,where n is odd. Then ,its square root will have..........digits
Answers
Answered by
121
If n is even then square root will have n/2 digits
If n is odd then square root will have (n+1)/2 digits
If n is odd then square root will have (n+1)/2 digits
alokraj121:
plz explain with example in both conditions
let perfect square be 160000 n =6 so the root is 400 n=6/2
Answered by
41
Answer:1/2(n+1)
Step-by-step explanation:If n is even then square root will have n/2 digits
If n is odd then square root will have (n+1)/2 digits
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