A given number is trebled to get a second number. This number is also trebled to get a third number. The sum of these three numbers is 12 more than 12 times the original number. Find the original number.
Answer (12)
Answers
Answered by
5
Answer:
let the original number be x
1st number =x
2nd number=3x
3rd number =9x
x + 3x + 9x = 12x + 12
13x = 12x + 12
13x - 12x = 12
x = 12
Answered by
5
Answer:
Let the original no. be x
1st no. = x
2nd no. = 3x
3rd no. = 9x
Sum of these no. = 12x + 12
So,
x + 3x + 9x = 12x + 12
13x. = 12x + 12
13x - 12x = 12
x = 12
➡️ ➡️ X = 12
The original no. Is 12
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