A given of sulphur dioxide mass occupies 500 me at 47°C. To what temperature must the gas be heated to change the volume to 650 ml ? Pressure is constant.
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Explanation:
A gas occupies 500 cm
3at normal temperature. At what temperature will the volume of the gas be reduced by 20% of its original volume, pressure being constant?
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Solution
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V = 500cm
3Normal temperature, t = 0 ∘ C = 0 + 273 K
V 1= Reduced volume + 20% of 500cm
3= 100
20×500 =100cm
3 Net, V 1 = 500 - 100 = 400cm
3T 1 = ?P = P 1From gas equation,PV
= T1P 1V 1273
P×500 = T1P×400
T1=5273×4= 218.4
= 218.4−273
= 54.60 ∘ C
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