Question

A given sample has 30% ethanol by mass, the rest being water. Determine the percentage C, H and O in the sample
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Answer 1

Explanation:

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Answer 2

Explanation:

ethanol = 30%

formula of ethanol = C2H5OH

• Molecular mass of ethanol =

12*2 + 5*1 + 16 + 1

= 46 g

percentage composition of C2

• 12*2/46 * 100 = 52.17%

percentage composition of H5 +H =

• 6/46 *100 = 13.04

percentage composition of O

• 16/46 *100=34.78

Water =100-30=70%

H2O

molecular mass = 2*1+16=18

percentage composition of H2 =

• 2/18*100=11.11%

percentage composition of O

• 16/18*100=88.88%