Question

A given sample has 30% ethanol by mass the rest
being water, Determine the percentage of C, H&O
in the given sample​

Answer 1

Answer:

12.5%C, 66.67%H, 20.83%O

Explanation:

Assume that we have total 10 molecules out of which 30% of them are ethanol and rest are of water i.e.

3 molecules of ethanol and 7 molecules of H2O

3(C2H5OH) + 7H2O

So from above equation total no. of atoms are

6C + 32H + 10O = 48

Divided each value of the no. of c,h,o with total no. of atoms we can get percentage of amount which will be constant for any amount as long as there is 30% ethanol and rest is water :)