A Given Sample of Na2SO4 contains 6.02*10^22 SO4- ions , Calculate the (i) number of Na+ ions and (ii) weight of the sample.
Answers
Answer:
Explanation:
Number of sulphate ions present = 6.02 x1022
Since 1 molecule of sodium sulphate on dissociation produced one sulphate ion.
Number of molecule of sodium sulphate present = 6.02 x1022
Therefore, number of formula units of sodium sulphate is 6.02 x1022
Answer: number of Na+ ions = 1.204*10^23
number of formula units= 6.02*10^22
weight of the sample = 14.2g
Explanation:
no of SO4- ions obtained on dissociation of 1 molecule of Na2SO4 = 1
no of Na+ ions obtained on dissociation of 1 molecule of Na2SO4 = 2
no of Na+ ions in the sample = 2*no of SO4- in the sample
=2*6.02*10^22
=12.04*10^22
=1.204*10^22--------(i)
As 1 SO4- ions obtained on dissociation of 1 molecule of Na2SO4 so
number of formula units = no of SO4- ions
=6.02*10^22-----------(ii)
Gram Molecular Mass of Na2SO4=142g=1 mole=6.023*10^2
142g=6.02*10^23
? =6.02*10^22
=142/10
=14.2g