Question

A given solution of NaOH contains 2.00 g of NaOH per litre of solution. Calculate the molarity of this solution.

Answer 1

weight of solute=2 gm
molecular mass of solute=40gm/mol
volume of solution=1

M=2/(40×1)
M=0.05mol/L

Answer 2

$\red{Answer}$

$\pink{ Molar \: mass \: of \: NaOH = 2.00 g}$

$\pink{2.00 \: gram \: of \: NaOH =}$

$\green{ \frac{2.00}{40.00} \: mole \: of \: NaOH = 0.05 \: mol \: NaOH}$

$\green{ molarity \: = \:\frac{mole \: of \: solute}{volume \: of \: solution \: in \: litre}}$

$\green{ = \frac{0.05}{1} = 0.05M}$