Question

A given wire has a resistance of 2.95 ohms per 1000 ft. A 74-ft extension cord made of this wire is used simultaneously with a food mixer that draws 8 A and an electric kettle that draws 16 A. If voltage source is constant at 120 V, what is the available voltage for the tools? How much power is lost in the extension cord?

Answer 1

Answer:

Part a)

Voltage across the two devices is 114.76 Volts

Part b)

Power loss across the extension chord is 125.7 W

Explanation:

Part a)

As we know that the two devices are connected in parallel with the voltage sources

So here we can say that total voltage across the given will remain same for all

so both the device will work at same voltage

$V_{out} = V - iR$

here we know that total current

$i = 8 A + 16 A = 24 A$

total resistance of the wire is given as

$R = \frac{2.95}{1000} (74) = 0.2183 ohm$

now we have

$V = 120 - 24(0.2183)$

$V = 114.76 V$

Part b)

Power loss across the extension chord is given as

$P = i^2 R$

$P = 24^2(0.2183)$

$P = 125.7 W$

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Topic : Electrical Power loss

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