Science, asked by akashkumaryadav6225, 1 year ago

a given wire of resistance 1Ω is streched to double its length.What will be its new resistance?

Answers

Answered by Anonymous
2

R = ρL / A

R = ρL^2 / V

When wire is stretched Volume (V) remains constant.

∴ R ∝ L^2

From above relation if length (L) is doubled resistance (R) will quadruple.

Hence, new resistance will be 4Ω

Answered by OoINTROVERToO
6

 \tt \: \blue{Resistnace \:  of \:  the \:  original \:  wire }   \\  \bf \: R  =  \frac{ ρL}{A},  \:  \:  \sf \: where  \: A= \frac{V}{L} \\  \\ \bf ⟹   R =  \frac{ρL²}{V} \\  \\ \cal \small { Now \:  its  \: length \:  is  \: stretched  \: such \:  that \:  new  \: length    }\\ \rm L′ = 2L \\  \\  \tt \: {Thus  \: resistance  \: of  \: the  \: wire}     \\   \rm \: R′ =  \frac{ρ(2L)²}{V} = 4R \\ \\ \red{  \small{ \bf Hence \:   \: resistance  \: becomes   \: 4   \: times  \: the  \: initial \:  resistance.}}

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