A gives B a start of 30m and beats him by 5 sec in a race of 300m . On another day he gives start A gives a start of 50m to B and still beats him by 1 sec. Find the velocity of B.(in m/s) (Assume both have been travelling at the constant speed through out) ca 5.
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Answers
Answer:
7777788m + 66778888890
Solution :-
Let time taken by b to complete the race is x seconds.
Case 1) :- A gives B a start of 30m and beats him by 5 sec in a race of 300m .
→ Distance covered by A = 300 m
→ Time taken by A = (x - 5) seconds .
so,
→ Speed of A = D/T = 300/(x - 5) m/s
and,
→ Distance covered by B = 300 - 30 = 270 m
→ Time taken by B = x seconds .
so,
→ Speed of B = D/T = (270/x) m/s
Case 2) :- A gives a start of 50 m to B and still beats him by 1 sec.
→ Distance covered by A = 300 m
→ Speed of A = 300/(x - 5) seconds .
→ Time taken by A = D/S = 300 * (x - 5)/300 = (x - 5) seconds .
and,
→ Distance covered by B = 300 - 50 = 250 m
→ Speed of B = (270/x) m/s
→ Time taken by B = D/S = 250 * (x/270) = (25x/27) seconds .
A/q,
→ (25x/27) - (x - 5) = 1
→ (25x - 27x + 135) / 27 = 1
→ 135 - 2x = 27
→ 2x = 108
→ x = 54 seconds .
therefore,
→ Speed of B = 270/54 = 5 m/s (Ans.)
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