Math, asked by pupanrockz2071, 1 year ago

A glass cylinder with diameter 20 cm haz water to a height of 9cm. A metal cube of 8 cm edge is immersed in it completely. Calculate the height by which water will rise in the cylinder.

Answers

Answered by dhillonrobin
18
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Answered by viji18net
1

Answer:

H = 9 cm

diameter = 20 cm so,radius = 10 cm

side of the cube = 8 cm

Total volume of the cylinder

(after cube is immersed) = Volume of water in cylinder + Volume of water displaced or volume of the cube

= 22/7*10*10*9 + 8*8*8

= 19800/7 + 512

= 2828.57 + 512

= 3340.57 cu cm

Now, height of water, h1 can be found by equating πr²h1 with this volume.

So,

22/7*10*10*h1 = 3340.57

h1 = (3340.57 × 7)/2200

h1 = 23383.99/2200

Height = 10.63 cm

Rise in the water level in the cylinder

= h1 - h

= 10.63 - 9

= 1.63 cm

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