A glass cylinder with diameter 20cm has water to a height of 9 CM. A metal cube of 8cm edge emerged in it completely. Find the height by which water will rise in cylinder.
Answers
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H = 9 cm
diameter = 20 cm so,radius = 10 cm
side of the cube = 8 cm
Total volume of the cylinder
(after cube is immersed) = Volume of water in cylinder + Volume of water displaced or volume of the cube
= 22/7*10*10*9 + 8*8*8
= 19800/7 + 512
= 2828.57 + 512
= 3340.57 cu cm
Now, height of water, h1 can be found by equating πr²h1 with this volume.
So,
22/7*10*10*h1 = 3340.57
h1 = (3340.57 × 7)/2200
h1 = 23383.99/2200
Height = 10.63 cm
Rise in the water level in the cylinder
= h1 - h
= 10.63 - 9
= 1.63 cm
__________________________
Answer:
H = 9 cm
diameter = 20 cm so,radius = 10 cm
side of the cube = 8 cm
Total volume of the cylinder
(after cube is immersed) = Volume of water in cylinder + Volume of water displaced or volume of the cube
= 22/7*10*10*9 + 8*8*8
= 19800/7 + 512
= 2828.57 + 512
= 3340.57 cu cm
Now, height of water, h1 can be found by equating πr²h1 with this volume.
So,
22/7*10*10*h1 = 3340.57
h1 = (3340.57 × 7)/2200
h1 = 23383.99/2200
Height = 10.63 cm
Rise in the water level in the cylinder
= h1 - h
= 10.63 - 9
= 1.63 cm