Math, asked by Urvichauhan9275, 1 year ago

A glass cylinder with radius of 7 cm has water upto a height of 9 cm .A metal cube of 5.5 cm edge is immersed in it completely .Calculate the height by which water rises in the cylinder

Answers

Answered by insaneabhi
3

Solution:-

H = 9 cm, diameter = 20 cm so, radius = 10 cm and side of the cube = 8 cm

Total volume of the cylinder (after cube is immersed) = Volume of water in cylinder + Volume of water displaced or volume of the cube

= 22/7*10*10*9 + 8*8*8

= 19800/7 + 512

= 2828.57 + 512

= 3340.57 cu cm

Now, height of water, h1 can be found by equating πr²h1 with this volume.

So,

22/7*10*10*h1 = 3340.57

h1 = (3340.57 × 7)/2200

h1 = 23383.99/2200

Height = 10.63 cm

Rise in the water level in the cylinder = h1 - h

= 10.63 - 9

= 1.63 cm

Answer.


insaneabhi: put your own value in it
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