Question

A glass flask of volume 400cm3 is just filled with mercury at 0°c.How much mercury will overflow when the temperature of the system rises to 80°C.​

Answer 1

Answer:-

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We know,

$\bold{γ _{glass} = \frac{ΔV}{V} } \\ \bold{ = > 1.2×10 {}^{ - 5} /C°}$

Also,

$\bold{γ _{mercury}=1.8×10 {}^{ - 4} /C°}$

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$➤ \bold{ΔV_{glass}=β _ {glass}V_0ΔT} \\ \bold{= > (1.2 \times 10 {}^{ - 5} )(400)(80 - 0) }\\ = >\bold{ \underline{\pink{0.38cm {}^{3}}}}$

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$➤ \bold{ΔV_{mercury}=β _ {mercury}V_0ΔT} \\ \bold{= > (1.8 \times 10 {}^{ - 5} )(400)(80 - 0) }\\ \bold{= > \underline{\blue{0.57cm {}^{3}}}}$

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Hence,

the amount of mercury that will overflow is =

$\bold{ΔV_{glass}-ΔV_{mercury}=0.57-0.38 }\\\bold{=> \underline{\red{0.19cm{}^{3}}}}$

[Stretch➡️➡️➡️for better view.]

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Hence, Shown.