a glass flask of volume 500 cm^3 is just filled with mercury at 0degree Celsius. How much overflows when the temperature of the system is raised to 80 degrees Celcius?
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γglass=VΔV=1.2×10−5ΔVglass=βglassV0ΔT=(1.2×10−5)(200)(100−20)=0.19cm3ΔVmercury=βmercuryV0ΔT=(1.8×10−5)(200)(100−20)=2.9cm3ΔVmercury−ΔVglass=2.9−0.19=2.7
Hence option (B) is correct.
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