Question

A glass is full of milk mixed with water in which one-fourth of the mixture is water. How much of it must be taken away and equal quantity of water be poured into the glass so that milk and water will be equal?​

Answer 1

According to your question,

There are 2 identical glasses i.e they have same shape and size.

One is filled with 1/3rd of its capacity and other one is filled 1/4 th of its capacity.

Now, remaining is filled with water in each glass.

Now,contents of both the glasses are mixed in a pot.

We need to find the ratio of milk to water in the pot in which contents of both the glasses are poured.

Let the capacity of each of the two glasses be C

Then,

According to your question,

1st glass: 1/3rd milk,remaining water

2nd glass: 1/4th milk,remaining water

So,in first glass,

(Milk/Water ratio)1=((1/3)/(1-1/3))=((1/3)/(2/3))=1/2

So,in second glass,

(Milk/Water ratio)2=((1/4)/(1-1/4))=((1/4)/(3/4))=1/3

Now these 2 glasses are mixed in a pot

(Milk/Water ratio)Pot=?

So,Let Capacity=L.C.M.(2,3) be 6 liters

Then,in first glass

Milk=2 liters

Water=4 liters

Then,in second glass

Milk=1.5 liters

Water=4.5 liters

Now these two glasses are mixed in a pot all quantities remaining constant

Total milk in pot=2 liters+ 1.5 liters= 3.5 liters

Total water in pot=4 liters+ 4.5 liters=8.5 liters

(Milk/Water)pot=3.5/8.5 or 7/17

Answer 2

Answer:

1/1

Step-by-step explanation:

since the total AMT of space in glass =1

if 1/4is water then 1/6 will be milk as we have to make it equal we hav to 1/1 water so that ratio becomes 1/5 that will be equal to milk