Question

A glass jar contains 6 red, 5 green, 8 blue and 3 yellow marbles. If two marbles are taken at
random from the jar with replacement, what is the probability of choosing
ila red marble and a yellow marble?
ii)2 green marbles ?
iii)a blue marble and a red marble ?
iv)2 yellow marbles?

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Answer 1

Answer:

8/25,6/25,7/25

Step-by-step explanation:

total number of marbles 25

for red marble drawing probability =total no of red/total no of marbles

                                                          =8/25

in the same way applies for green and blue probabilty findings..i.e., 6/25 and 7/25 respectively

Hope it helps...

Answer 2

Step-by-step explanation:

1.) Total Marbles = 6+5+8+3 =22.

i.) $\frac{6}{22} + \frac{3}{22}$ = $\frac{9}{22}$

ii.)$\frac{5}{22} + \frac{5}{22}$ = $\frac{10}{22}$  or $\frac{5}{22}^{2}$ =  $\frac{10}{22}$

iii.)$\frac{8}{22} + \frac{6}{22}$ = $\frac{14}{22}$

iv.) $\frac{3}{22}^{2}$ = $\frac{6}{22}$