Question

A glass marble projected horizontally from the top
of a table of height 'h' falls at a distance 'x' from
the edge of the table. The velocity of projection is
o
(1)
c
(2)
2x
2h
(3) gxh
(4) gx+h
​

Answer 1

Answer:

The velocity of projection is

=

x

⋅

√

g

2

h

m

s

−

1

Explanation:

Let the horizontal velocity of projection be

=

v

m

s

−

1

The height of the table is

=

h

m

The acceletation due to gravity is

g

=

9.8

m

s

−

2

Applying the equation of motion

s

=

u

t

+

1

2

a

t

2

The vertical component is

u

=

0

m

s

−

1

h

=

0

+

1

2

g

t

2

t

=

√

2

h

g

The horizontal distance is

)

x

m

Therefore,

x

=

v

⋅

√

2

h

g

v

=

x

⋅

√

g

2

h