A glass marble projected horizontally from the top
of a table of height 'h' falls at a distance 'x' from
the edge of the table. The velocity of projection is
o
(1)
c
(2)
2x
2h
(3) gxh
(4) gx+h
Answers
Answered by
2
Answer:
The velocity of projection is
=
x
⋅
√
g
2
h
m
s
−
1
Explanation:
Let the horizontal velocity of projection be
=
v
m
s
−
1
The height of the table is
=
h
m
The acceletation due to gravity is
g
=
9.8
m
s
−
2
Applying the equation of motion
s
=
u
t
+
1
2
a
t
2
The vertical component is
u
=
0
m
s
−
1
h
=
0
+
1
2
g
t
2
t
=
√
2
h
g
The horizontal distance is
)
x
m
Therefore,
x
=
v
⋅
√
2
h
g
v
=
x
⋅
√
g
2
h
Similar questions