Question

A
glass marble
whose
mass is
20gm falls
from a
height of 0.25m and rebounds to a height of 1.6m.
If g = 9.8m/s^2, find the
impulse acting on
the fall ( in N-s)
​

Answer 1

Answer:

impulse=FΔt=mΔv

so we have to find the velocity with which ball strikes the ground : v

1

​

=

2gh

​

=

2×10×20

​

=20

s

m

​

and for finding speed with which it rebounds such that it goes to a height of 5m will be

v

2

​

=

2gh

​

=

2×10×5

​

=10

s

m

​

so, impulse=m(v

2

​

−v

1

​

)=0.10×(20−10)=1N−s

F=

dt

dP

​

=1/0.01=100N

Explanation:

Answer 2

Answer:

hope it clears...

Good luck