Question

a glass paper-weight (n=1.5) of radius 3 cm has a tiny air buuble trapped inside it. closest distance of the bubble from the surface is 2 cm. where will it appear when seen from the other end (from where it is farthest)?​

Answer 1

Answer:

ANSWER

Using the formula for refraction through curved surfaces,

v

N

2

−

u

N

1

=

R

N

2

−N

1

v

1

−

−3

1.5

=

−5

1−1.5

v

1

+0.5=0.1

v

1

=−0.4

v=−

4

10

=−2.5cm

Explanation:

Answer: The bubble will appear 3.03 cm below the surface.