a glass prism of angle 72⁰ and refractive index 1.66 is immersed in a liquid of refractive index 1.33. find the angle minimum deviation for the falling of the prism.
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A glass prism apex angle 72o and refractive index 1.66 is immersed in a liquid of refractive index 1.33. What is the angle of minimum deviation for a parallel beam of light passing through the prism?
The prism formula is μ=sin(A+δm2)sin(A2), where μ,A and δm are the refractive index of the material of the prism with respect to that of the medium from which the ray of light is entering the prism, the angle of the prism and the angle of minimum deviation respectively.
From the prism formula we get a formula for the angle of minimum deviation of the prism as δm=2arcsin(μsin(A2))−A.
It is given that A=72o.
μ=μglassμliquid=1.661.33.
⇒δm=2arcsin(μsin(A2))−A=2arcsin(1.661.33sin(72o2))−72o
=2arcsin(1.661.33sin(36o))−72o=22.3826o
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