Question

A glass prism of refracting angle 60° and refractive index 1.5 is completely immersed in water of refractive index 1.33. Calculate the angle of minimum deviation of the prism in this situation, sin-1 0.56 = 34.3°.

Answer 1

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Answer 2

Answer:

Explanation:

Refracting angle of glass prism = A = 60° (Given)

Refractive index of glass prism = 1.5 (Given)

Refractive index of water = 1.33 (Given)

Refractive index of the material of the prism = µ

The refractive index -

µ1 = sin (A + δ)/2/ sin A/2

= sin{(60+Dm)/2}/sin30° = 1.5/1.33

= sin{30+(Dm/2)} =1.5×(1/2 )= 1.12

= 30°+(Dm/2) =sin-1(0.75) = 38.43

= (Dm/2) = 38.43–30

= 8.43°