Question

A glass rod when rubbed with a piece of fur acquires a charge of magnitude 3.2 μC.
The number of electrons transferred is

Answer 1

Answer:

Q=ne

3.2× 10^-6= n × 1.6× 10^-19

n= .3.2× 10^-6÷ 1.6× 10^-19

Answer 2

Here we use the equation,

Q = ne where Q is the charge

                         n is the number of electrons transferred

                         e is the basic electronic charge

From the eqaution

Q = ne

3.2×10⁻⁶ = n×1.6×10⁻¹⁹

n = 3.2/1.6 × 10⁻⁶/10⁻¹⁹

n = 2×10¹⁹⁻⁶ = 2×10¹³

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