A glass slab 2.5cm thick is placed over a coin. If the refractive index of glass is 3/2, find the height through which coin is raised. [NO FAKE ANSWER!! OTHERWISE I WILL REPORT]
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refractive index= real depth/apparent depth
3/2 = 2.5/apparent depth
apparent depth = 5/3 cm
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Question :
A glass slab 2.5cm thick is placed over a coin. If the refractive index of glass is 3/2, find the height through which coin is raised.
Answer :
The height by which the coin appears to be raised is 0.83cm.
Given :
Thickness of glass slab (Real depth) = 2.5 cm
Refractive index of glass = 3/2
To find :
Height through which the coin is raised
Solution :
We know,
Refractive index = Real depth / apparent depth
=> 3/2 = 2.5 / Apparent depth
=> Apparent depth = 2.5 ÷ 3/2
= 2.5 × 2 / 3
= 1.67
Hence, The height by which it appears to be raised is = (2.5 - 1.67) cm
= 0.83 cm
Therefore, The height by which the coin appears to be raised is 0.83cm.
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